Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 49: 27

Answer

$35~mi/h$

Work Step by Step

$15~min=\frac{1}{4}~h=0.25~h$ The first 15 minutes: $distance=(average~speed)(time~elapsed)=(5~mi/h)(0.25~h)=1.25~mi.$ Now, I need to travel 8.75 miles, in the 15 minutes (0.25 h) remaining: $average~speed=\frac{distance}{time~elapsed}=\frac{8.75~mi}{0.25~h}=35~mi/h.$
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