Physics Technology Update (4th Edition)

(a) $Average$ $speed=9.934\times10^{-2}m/s$ (b) $Average$ $speed=0.2222mi/h$
$10months=(10 months)(\frac{30days}{1month})(\frac{24h}{1day})=7200h$ $7200h=(7200h)(\frac{3600s}{1h})=2.592\times10^{7}s$ $1600 mi = (1600mi)(\frac{5280ft}{1mi})(\frac{1m}{3.281ft})=2.575\times10^{6}m$ (a) $Average$ $speed=\frac{distance}{time elapsed}=\frac{2.575\times10^{6}}{2.592\times10^{7}}=9.934\times10^{-2}m/s$ (b) $Average$ $speed=\frac{distance}{time elapsed}=\frac{1600mi}{7200h}=0.2222mi/h$