Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 49: 13

Answer

$Time~elapsed=2.57s$

Work Step by Step

From Earth to the Moon $= 2.39\times10^{5}mi$ From Earth to the Moon and back = $2\times2.39\times10^{5}mi=4.78\times10^{5}mi$ $Time~elapsed=\frac{distance}{average~speed}=\frac{4.78\times10^{5}mi}{1.86\times10^{5}mi/s}=2.57s$
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