Answer
a) $W=22.0KJ$
b) $Q=22.0KJ$
c) The work done is increased by a factor of two.
Work Step by Step
(a) We know that
$W=nRTln(\frac{V_f}{V_i})$
We plug in the known values to obtain:
$W=(8.00)(8.31)(245)ln(\frac{4.33}{1.12})$
$W=22.0KJ$
(b) As $Q=\Delta U+W$
$\implies Q=0+22.0KJ$
$Q=22.0KJ$ (positive heat flow into the gas)
(c) As we know that work done is proportional to the number of moles of the gas, the work done is increased by a factor of two.
