Answer
$0.013m^3$
Work Step by Step
We know that
$P\Delta V=W$
$P(V_f-V_i)=W$
$P(\frac{1}{2}V_i-V_i)=W$
This can be rearranged as:
$V_i=\frac{-2W}{P}$
We plug in the known values to obtain:
$V_i=\frac{-2(-790)}{120\times 10^3}=0.013m^3$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 644: 14
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