Answer
(a) zero
(b) $5.1\times 10^{-3}m^3$
Work Step by Step
(a) We know that
$\Delta U=Q-W$
This can be rearranged as:
$W=Q-\Delta U$
$\implies P\Delta V=Q-\Delta U$ (As $W=P \Delta V$)
This can be rearranged as:
$\Delta V=\frac{Q-\Delta U}{P}$
We plug in the known values to obtain:
$\Delta V=\frac{920-920}{110\times 10^3}$
$\Delta V=0$
(b) We know that
$\Delta U=Q-W$
This can be rearranged as:
$W=Q-\Delta U$
$\implies P\Delta V=Q-\Delta U$ (As $W=P \Delta V$)
This can be rearranged as:
$\Delta V=\frac{Q-\Delta U}{P}$
We plug in the known values to obtain:
$\Delta V=\frac{920-360}{110\times 10^3}$
$\Delta V=5.1\times 10^{-3}m^3$
