Answer
(a) $\alpha=-29.6\frac{rev}{s^2}$
(b) $s=242ft$
Work Step by Step
(a) We know that
$\alpha=\frac{\omega-\omega_{\circ}}{t}$
We plug in the known values to obtain:
$\alpha=\frac{0-(144\frac{rev}{min}\times \frac{1min}{60s})}{2.50s}$
$\alpha=-29.6\frac{rev}{s^2}$
(b) As $\Delta \theta=\frac{1}{2}(\omega+\omega_{\circ})t$
$\Delta \theta=\frac{1}{2}(0+4440)(2.50\times \frac{1min}{60s})=92.5rev$
We also know that
$s=r\Delta \theta$
We plug in the known values to obtain:
$s=(\frac{1}{2}\times 10.0\frac{in}{12in /ft})(92.5\times 2\pi)=242ft$
