Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 324: 15

Answer

$\Delta \theta=3.78\ rad$

Work Step by Step

We know that $\Delta \theta=\frac{\omega^2-\omega_{\circ}^2}{2\alpha}$ We plug in the known values to obtain: $\Delta \theta=\frac{2.45-3.40}{2(-0.736)}$ $\Delta \theta=3.78\ rad$
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