Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - General Problems - Page 258: 77

Answer

$2.646\times 10^{-4}m^2$

Work Step by Step

The force in the left vertical support column is $44100N$, in compression. We want a steel column that can handle three times that or $132300N$. Steel has a compressive strength of $500\times10^6N/m^2$. Use this to find the area. $$\frac{F}{A}=\frac{132300N}{A}=500\times 10^6 N/m^2$$ $$A=\frac{132300N}{500\times10^6 N/m^2}=2.646\times10^{-4}m^2$$
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