Answer
See answer.
Work Step by Step
Find the average acceleration of the person.
$$0^2 = (-55m/s)^2+2a(-1.0m)$$
$$a=1513\;m/s^2$$
Find the average force of the snow on the person. Use Newton’s second law.
$$F_{snow}-mg=ma$$
$$F_{snow}=m(a+g)=(75\;kg)( 1513+9.8\;m/s^2)$$
Calculate the average force per unit area on the body.
$$\frac{F_{snow}}{A}=\frac{(75\;kg)( 1513+9.8\;m/s^2)}{0.30\;m^2}=3.81\times10^5\;N/m^2$$
This is less than the quoted strength of body tissue, so serious injury may be avoided.
