Answer
4300 rev.
Work Step by Step
4300 revolutions.
Each time the tire makes one revolution, it travels a distance $\pi D$ along the floor, where D is the diameter.
$$N rev\frac{\pi 68 \times 10^{-2}m}{1 \; rev}=9200 m$$
Solve for $N \approx 4300 \; rev $.
