## Physics: Principles with Applications (7th Edition)

$9.3 \times 10^{-2}m$.
Each time the ball makes one revolution, it travels a distance $\pi D$ along the floor. $$12.0 rev\frac{\pi D \, meters}{1 rev}=3.5 \, m$$ Solve for $D \approx 9.3 \times 10^{-2}\,m$.