Answer
(a) $\omega = 754~rad/s$
(b) $v = 22.6~m/s$
(c) $4.5\times 10^7~bits/s$
Work Step by Step
(a) $\omega = (7200~rpm)(2\pi \frac{rad}{rev})(\frac{1~m}{60~s}) = 754~rad/s$
(b) $v = \omega r = (754~rad/s)(0.0300~m) = 22.6~m/s$
(c) Let $N$ be the number of bits which can be read each second. Then,
$N = \frac{v}{l} = \frac{22.6~m/s}{0.50\times 10^{-6}~m/bit} = 4.5\times 10^7~bits/s$
