Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems - Page 195: 56

Answer

10.885 kg

Work Step by Step

Take both the upper leg and lower leg together. Value in Table 7-1 gives us the relative mass of both legs so for value of only one leg, a factor of 1/2 have to be included. Assume a person's mass is 70 kg. $$70kg\times\frac{(21.5+9.6)}{100}\times\frac{1}{2}=10.885kg$$
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