Answer
$-16.7\%$
It is outside the body
Work Step by Step
We only need to calculate the y value of the center of mass
and lets take the y value of the horizontal head, trunk, and thighs
$y_{CM}=\frac{-(6.6kg)(81.2m-71.7m)-(4.2kg)(81.2m-55.3m)-(1.7kg)(81.2m-43.1m)-(9.6kg)(28.5m-18.2m)-(3.4kg)(28.5m-1.8m)}{6.6kg+4.2kg+1.7kg+9.6kg+3.4kg}=-16.7\%$
It is outside the body
