Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 165: 38

Answer

a) $7.71\frac{m}{s}$ b) $x=0.26m$

Work Step by Step

$E_K=\frac{mv^2}{2}$ $E_P=mgh$ a) $\frac{m(v_i)^2}{2}=\frac{mv^2}{2}-mgh$ $v=\sqrt{(v_i)^2+2gh}=\sqrt{(4.5\frac{m}{s})^2+2(9.8\frac{m}{s^2})(2.0m)}=7.71\frac{m}{s}$ b) $\frac{mv^2}{2}=\frac{kx^2}{2}-mgx$ $\frac{(62kg)(7.71)^2}{2}=\frac{(5.8\times10^4\frac{N}{m})x^2}{2}-(62kg)(9.8\frac{m}{s^2})x$ $0=29000x^2-608x-1840$ $x=0.26m$
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