Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 165: 34

Answer

$v_0 = 6.4~m/s$

Work Step by Step

We can use conservation of energy to solve this question: $KE_0 = KE_f + PE_f$ $\frac{1}{2}mv_0^2 = \frac{1}{2}mv_f^2 + mgy$ $v_0^2 = v_f^2 + 2gy$ $v_0 = \sqrt{v_f^2 + 2gy}$ $v_0 = \sqrt{(0.50 ~m/s)^2 + (2)(9.80 ~m/s^2)(2.10 ~m)}$ $v_0 = 6.4~m/s$
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