Answer
$\mu_s= 1.4$
Work Step by Step
$x = \frac{1}{2}at^2$
$a = \frac{2x}{t^2}$
$a = \frac{(2)(1000 ~m)}{(12 ~s)^2}$
$a = 14 ~m/s^2$
The force of static friction between the tires and the asphalt provided the force to accelerate the drag racer.
$F_f = ma$
$mg ~\mu_s = ma$
$\mu_s = \frac{a}{g}$
$\mu_s = \frac{14 ~m/s^2}{9.8 ~m/s^2}$
$\mu_s = 1.4$
The coefficient of static friction $\mu_s$ is 1.4.
