Answer
17.59 MeV.
Work Step by Step
Calculate the Q-value, using data from Appendix B. We use atomic masses.
$$Q=\left(m(^{2}_{1}H)+m(^{3}_{1}H)-m(^{4}_{2}He)-m_{n} \right)c^2$$
$$ =\left(2.014102u+3.016049u-4.002603u-1.008665u\right)c^2\left( \frac{931.49MeV/c^2}{u}\right)$$
$$=17.59MeV$$
The Q-value is positive. The fusion reaction is exothermic, and releases 17.59 MeV of energy.