Answer
See answer.
Work Step by Step
Using the hint, the average translational kinetic energy of a proton is $\frac{3}{2}kT$.
$$\frac{3}{2}kT=\frac{3}{2}(1.38\times10^{-23}J/K)(2\times10^7K)=4\times10^{-16}J$$
This is about $3\times 10^3 eV$.
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - Problems - Page 911: 27
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