Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 29 - Molecules and Solids - Problems - Page 854: 7

Answer

See work below.

Work Step by Step

The units of $\frac{\hbar^2}{I}$ are: $$\frac{(J \cdot s)^2}{kg \cdot m^2}=\frac{J^2}{(kg \cdot m/s^2)m}=\frac{J^2}{N\cdot m}=J$$ The unit is a joule, which is a unit of energy.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.