Answer
See answers.
Work Step by Step
As requested, convert the units from kcal/mole to eV/molecule.
$$1\frac{kcal}{mole}\times\frac{4186J}{1kcal}\times\frac{1eV}{1.602\times10^{-23}J}\times\frac{1\;mole}{6.022\times10^{23}molecules}$$
$$=4.339\times10^{-2}\frac{eV}{molecule}$$
Reverse the process to change 4.43 eV per KCl molecule into kcal per mole.
$$4.43\frac{eV}{molecule}\times\frac{1\;kcal/mole}{4.339\times10^{-2}eV/molecule}=102\;kcal/mole$$
