Answer
See work below.
Work Step by Step
The uncertainty in the velocity is the product of the velocity and the measuring precision. Calculate the uncertainty in the position by using equation 28–1.
$$\Delta x_{electron} \geq \frac{\hbar}{\Delta p}=\frac{\hbar}{m \Delta v}$$
$$=\frac{1.055\times 10^{-34}J \cdot s}{(9.11\times10^{-31}kg)(120m/s)(0.00065)}$$
$$=1.485\times 10^{-3}m\approx 1.5\times10^{-3}m$$
$$\Delta x_{baseball} \geq \frac{\hbar}{\Delta p}=\frac{\hbar}{m \Delta v}$$
$$=\frac{1.055\times 10^{-34}J \cdot s}{(0.14kg)(120m/s)(0.00065)}$$
$$=9.661\times 10^{-33}m\approx 9.7\times10^{-33}m$$
The uncertainty in the electron's position is $1.5\times10^{29}$ times greater.
