Answer
$ 2.6\times10^{-25}s $
Work Step by Step
Find the lifetime using the uncertainty in the energy, and equation 28–2.
$$\Delta t \geq \frac{\hbar}{\Delta E}$$
$$=\frac{1.055\times 10^{-34}J \cdot s}{(2.5 GeV)(1.60\times10^{-10}J/GeV)}$$
$$=2.6\times10^{-25}s $$
