Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 28 - Quantum Mechanics of Atoms - Problems - Page 826: 2

Answer

$L=4.5\times10^{27}m$

Work Step by Step

$\lambda=\frac{h}{p}=\frac{h}{mv}=2.7608\times10^{-33}m$ Using the formula $\theta=\frac{1.22\lambda}{D}=\frac{1.22(2.7608\times10^{-33}m)}{3.00\times10^{-3}m}=1.1227\times10^{-30}rad$ $\tan(\theta)=\theta=\frac{x}{2L}$ $L=\frac{x}{2\theta}=4.5\times10^{27}m$
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