Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - Problems - Page 709: 41

Answer

The second order.

Work Step by Step

Use equation 24–4 to find the order. The maximum angle is 90 degrees. The number of slits per cm is the reciprocal of the slit width (measured in cm). $$d sin \theta = m \lambda $$ $$m=\frac{d sin \theta}{ \lambda }$$ $$=\frac{(\frac{1}{6500}cm)(sin 90^{\circ})}{6.33\times10^{-5}cm}$$ $$=2.43$$ The second order is the highest spectral order that can be seen.
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