Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - Problems - Page 709: 33

Answer

329 nm

Work Step by Step

The slit separation is $d=\frac{1}{3800}cm$. Use equation 24–4 to find the wavelength. $$d sin \theta = m \lambda $$ $$\lambda=\frac{d sin \theta}{m}$$ $$\lambda=\frac{(\frac{1}{3800}cm)(sin 22.0^{\circ})}{3}$$ $$=3.29\times10^{-5}cm$$
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