Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - Problems - Page 709: 32

Answer

$4.3^{\circ}$

Work Step by Step

Use equation 24–4 to find the angle for the second-order maximum. $$d sin \theta = m \lambda $$ $$\theta =sin^{-1}(\frac{m \lambda}{d})$$ $$ =sin^{-1}(\frac{2 (510\times10^{-9}m)}{1.35\times10^{-5}m})$$ $$=4.3^{\circ}$$
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