Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - Problems - Page 708: 19

Answer

$\Delta \theta_{refraction} = 0.23^{\circ}$

Work Step by Step

Find the angles of refraction using Snell’s law. Here “1” designates air, and “2” designates the glass. First piece of glass: $$n_1sin\theta_1= n_2sin\theta_2$$ $$\theta_2=sin^{-1}(\frac{n_1}{n_2}sin\theta_1) $$ $$=sin^{-1}(\frac{1.00}{1.4831}sin65.00^{\circ}) =37.67^{\circ}$$ Second piece of glass: $$\theta_2=sin^{-1}(\frac{1.00}{1.4754}sin65.00^{\circ}) =37.90^{\circ}$$ The difference in refraction angles is $\Delta \theta_2 = 0.23^{\circ}$.
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