Answer
2.2 mm
Work Step by Step
The spacing on the screen between bright fringes is addressed in Example 24-1.
For light shining through 2 slits separated by a distance d, the spacing between successive fringes on a screen a distance $\mathcal{l}$ away is $\Delta x = \frac{\lambda \mathcal{l}}{d}$.
$$\Delta x = \frac{(544\times10^{-9}m)(4.0m)}{0.0010m}$$
$$\Delta x = 2.2\times10^{-3}m$$
