Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - Problems - Page 708: 10

Answer

$d=9.0\times10^{-6}m $

Work Step by Step

The spacing on the screen between bright fringes is addressed in Example 24-1. For light shining through 2 slits separated by a distance d, the spacing between successive fringes on a screen a distance $\mathcal{l}$ away is $\Delta x = \frac{\lambda \mathcal{l}}{d}$. Here, the spacing $\Delta x$ is 0.35 m. Solve for the slit spacing d. $$\Delta x = 0.35m= \frac{(633\times10^{-9}m)(5.0m)}{d }$$ $$d=9.0\times10^{-6}m $$
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