Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 40

Answer

a) $n_2=1.41$ b) $n_2=1.88$

Work Step by Step

a) $n_2=\frac{\sin(\alpha)}{\sin(\beta)}$ $n_2\sin(\gamma)=n_1\sin(\theta)$ $n_2=\frac{1}{\sin(\gamma_{min})}$ $90^o=\beta+\gamma_{min}$ $n_2=\frac{\sin(\alpha_{max})}{\sin(90^o-\gamma_{min})}=\frac{1}{\sin(\gamma_{min})}$ $\cos(\gamma_{min})=\sin(\gamma_{min})$ $\gamma_{min}=45^o$ $n_2=\frac{1}{\sin(\gamma_{min})}=\frac{2}{\sqrt{2}}=1.41$ b) $n_2=\frac{1.33}{\sin(\gamma_{min})}=1.88$
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