Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 38

Answer

$n_l=1.45$

Work Step by Step

$\theta_1=\arctan{\frac{7.6cm}{8.0cm}}=43.5^o$ $n_l=\frac{1}{\sin(43.5^o)}=1.45$
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