Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 35


$61.0^{\circ}$; The light must start in the crown glass.

Work Step by Step

Total internal reflection happens when the light in the material with a higher index is incident upon an interface. The light must start in the crown glass. At the critical angle, the refracted angle is $90^{\circ}$. Find the critical angle of incidence using Snell’s law. Here “1” designates crown glass, and “2” designates water. $$n_1sin\theta_1= n_2sin\theta_2$$ $$\theta_1=sin^{-1}(\frac{n_2}{n_1}sin90^{\circ}) $$ $$=sin^{-1}(\frac{1.33}{1.52}sin90^{\circ}) =61.0^{\circ}$$
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