Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - General Problems - Page 556: 75

Answer

The terminal voltage of the three mercury cells in series is higher than the terminal voltage of the 3 dry cells.

Work Step by Step

P=IV, so divide the 2.5 watts of power by the required voltage to find the current passing through the hearing aid. $$I=\frac{P}{V}=\frac{2.5W}{4.0V}=0.625A$$ Use equation 19-1 to calculate the terminal voltage across the series combinations of three batteries. $$V_{mercury}=3[\epsilon-Ir]=3[1.35V-(0.625A)(0.030\Omega)=3.99V$$ $$V_{dry}=3[\epsilon-Ir]=3[1.50V-(0.625A)(0.35\Omega)=3.84V$$ The terminal voltage of the three mercury cells in series is closer to 4.0V, and is higher than the terminal voltage of the 3 dry cells. The mercury cells will be a better choice for the hearing aid.
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