Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - General Problems - Page 556: 69

Answer

4C, 2.5C, 5/3C, 4/3C, C, 3/4C, 3/5C, 2/5C, 1/4C

Work Step by Step

$C+C+C+C=4C$ $C+C+\frac{C}{2}=2.5C$ $C+\Big(\frac{1}{\frac{1}{2C}+\frac{1}{C}}\Big)^{-1}=\frac{5}{3}C$ $C+\frac{C}{3}=\frac{4}{3}C$ $\frac{C}{2}+\frac{C}{2}=C$ $\Big(\frac{1}{\frac{1}{3C}+\frac{1}{C}}\Big)^{-1}=\frac{3}{4}C$ $\Big(\frac{1}{\frac{1}{C}+\frac{C}{2}+C}\Big)^{-1}=\frac{3}{5}C$ $\Big(\frac{1}{\frac{1}{C}+\frac{1}{C}+\frac{1}{2C}}\Big)^{-1}=\frac{2}{5}C$ $\frac{C}{4}$
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