Answer
a. 0.13A.
b. 0.13 A.
c. 39 mA.
Work Step by Step
Use Ohm’s law to find the current.
$$I=\frac{120V}{950\Omega}=0.126A\approx 0.13A$$
b. The lower-resistance path is an alternate way to ground, so the path is in parallel with the body. The body still has 120V across it, so the answer is unchanged.
c. The total current is limited to 1.5 A.
The body’s resistance of $950\Omega$ is 38 times higher than the lower resistance path of $25\Omega$. Since the same voltage drop is applied across each, then Ohm’s law tells us that the low-resistance path will conduct 38 times the current that passes through the body.
The sum of these currents is 1.5 amps.
$$I_{body}+I_{low-R\;path} = I_{body}+38I_{body}=1.5A$$
$$I_{body}=\frac{1.5A}{39}\approx 38\times10^{-3}A$$
This is still dangerous.
