Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 523: 58

Answer

$7\times 10^6 V/m$

Work Step by Step

The magnitude of the electric field, assumed to be constant, is the voltage change divided by the distance. $$|E|=\frac{\Delta V}{\Delta x}$$ $$=\frac{70 \times10^{-3}V}{1.0\times 10^{-8}m}=7.0\times 10^6 V/m$$
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