Answer
0.12 amps
Work Step by Step
Use Ohm’s law, equation 18–2, and the relationship between peak and rms values, equations 18–8a and 18-8b.
$$I_{peak}=\sqrt2I_{rms}=\sqrt{2}\frac{V_{rms}}{R}$$
$$ =\sqrt{2}\frac{220V}{2700\Omega}=0.12A$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 18 - Electric Currents - Problems - Page 523: 47
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
