Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 521: 8

Answer

4.1 mV

Work Step by Step

First, find the resistance between the bird’s feet. $$R=\frac{2.5\times10^{-5}\Omega}{m}(4.0\times10^{-2}m)=1.0\times10^{-6}\Omega$$ Next, use equation 18–2, which defines the resistance, to find the potential difference. $$V=IR=(4100A)( 1.0\times10^{-6}\Omega)= 4.1\times10^{-3}V$$
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