Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 521: 5

Answer

1200 volts

Work Step by Step

Use equation 18–2, which defines the resistance. $$V=IR=(0.25A)(4800\Omega)=1200\;volts$$
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