Answer
$6.2\times10^{-11}A$
Work Step by Step
Use the definition of current, equation 18–1.
$$I=\frac{\Delta Q}{\Delta t}$$
$$I=\frac{(1200\;ions)(1.60\times10^{-19}C/ion)}{3.1\times10^{-6}s}=6.2\times10^{-11}A$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 18 - Electric Currents - Problems - Page 521: 3
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