Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 521: 16

Answer

The cut should be made at 0.80 of the way along the wire (or, equivalently, at 0.20 of the way).

Work Step by Step

Equation 18-3 shows that the resistance is directly proportional to the length of the wire. The length of the longer, higher-resistance piece should be 4.0 times the length of the shorter, lower-resistance piece. Make the cut at 0.80 of the way along the wire (or, equivalently, at 0.20 of the way). The resistance of the longer piece is $0.8 \times 15.0\Omega = 12.0\Omega$, and that of the shorter piece is $0.2 \times 15.0\Omega = 3.0\Omega$. The sum of the resistances of the two wires in series is the original $15.0\Omega$.
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