Answer
a. $\frac{1}{12}$
b. $\frac{1}{12}$
Work Step by Step
When throwing a pair of dice, the number of possible microstates is 36.
a. There are 3 microstates that have a total of 4: (1)(3), (2)(2), and (3)(1). The probability of rolling a 4 is $\frac{3}{36}=\frac{1}{12}$.
b. There are 3 microstates that have a total of 10: (4)(6), (5)(5), and (6)(4). The probability of rolling a 10 is $\frac{3}{36}=\frac{1}{12}$.
