Answer
$-1.22\times10^6J/K$
Work Step by Step
Heat leaves the water, so the change in entropy is negative. The heat transfer is the water’s mass multiplied by the heat of fusion.
$$\Delta S=\frac{Q}{T}=-\frac{mL_{fusion}}{T}$$
$$=-\frac{(1.00\times10^3kg)(3.33\times10^5J/kg)}{ 273K}$$
$$=-1.22\times10^6J/K$$
