Answer
20 W
Work Step by Step
Estimate the rate of heat flow using equation 14–5.
$$\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$$
$$=(\frac{0.2 J}{s \cdot m \cdot C^{\circ}})(1.5m^2)\frac{37^{\circ}C-(34^{\circ}C)}{0.04m}$$
$$\approx20W$$
This process only provides about 10 percent of the needed cooling capacity.
