Answer
11 food Calories
Work Step by Step
Use equation 14–2.
$$Q=mc\Delta T=(0.35kg)(\frac{1.00kcal}{kg})(37^{\circ}C-5^{\circ}C)=11.2kcal=11Cal$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 14 - Heat - General Problems - Page 410: 46
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