Answer
a. 35 W
b. 5500 W
Work Step by Step
Calculate the rate of heat flow using equation 14–5.
a. $\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$
$$=(\frac{0.025 J}{s \cdot m \cdot C^{\circ}})(0.95m^2)\frac{34^{\circ}C-(-18^{\circ}C)}{0.035m}$$
$$=35W$$
b. $\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$
$$=(\frac{0.56 J}{s \cdot m \cdot C^{\circ}})(0.95m^2)\frac{34^{\circ}C-(-18^{\circ}C)}{0.005m}$$
$$=5500W$$
