Answer
2.60 mol
10.4 g
Work Step by Step
Use the ideal gas law, PV=nRT.
$$n=\frac{PV}{RT}=\frac{(1.08)(1.013\times10^5Pa)\frac{4}{3}\pi(0.240m)^3}{(8.314 J/(mol \cdot K))(293K)}=2.60mol$$
Now find the mass.
$$2.60mol\frac{4.00g}{1mol}=10.4g$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 13 - Temperature and Kinetic Theory - General Problems - Page 388: 78
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