Answer
2.9 nJ.
Work Step by Step
The intensity of $I = 1.0\;W/m^2$ can be found from Table 12-2.
Consider a square, of area A, perpendicular to the direction of travel of the sound wave.
Recall that intensity is defined to be energy impinging across an area, per unit time, perpendicular to the direction of wave travel. By the definition, in a time $\Delta t$, an amount of energy $IA \Delta t$ moves through the square, and since the energy moves at speed v, it is contained in a volume of $(A)(v)\Delta t$.
Now we find the energy contained in a cubic centimeter. The relevant time $\Delta t$ is the time needed for the sound wave to travel 1.0 cm. The relevant area A is a square, 1.0 cm on a side.
$$\Delta E=IA\Delta t=(1.0\;W/m^2)(0.010m)^2\frac{0.010m}{343m/s}=2.9\times10^{-9}J$$
